11p+4=3p^2

Solution for 11p+4=3p^2 equation:

11p+4=3p^2

We move all terms to the left:

11p+4-(3p^2)=0

determiningTheFunctionDomain
-3p^2+11p+4=0

a = -3; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·(-3)·4
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-13}{2*-3}=\frac{-24}{-6}
=+4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+13}{2*-3}=\frac{2}{-6}
=-1/3
$